Number to English Project

Practity 11 March, 2024 13 0

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Number to English Converter Project

Write a Python script that requests the user to enter an integer and return the English name of that number.
You should support both positive and negative numbers. Do not use the inflect library.

Tip

Solve this programming challenge breaking down the number into smaller parts (billions, millions, thousands, and hundreds) and handle each part separately. It is a Python conditionals practice project to level up your problem solving skills and your conditional statements knowledge

Expected Output

Enter a number: 10569
## Output
ten thousand, five hundred and sixty-nine

Source code


def int_to_en(num):
    d = { 0 : 'zero', 1 : 'one', 2 : 'two', 3 : 'three', 4 : 'four', 5 : 'five',
          6 : 'six', 7 : 'seven', 8 : 'eight', 9 : 'nine', 10 : 'ten',
          11 : 'eleven', 12 : 'twelve', 13 : 'thirteen', 14 : 'fourteen',
          15 : 'fifteen', 16 : 'sixteen', 17 : 'seventeen', 18 : 'eighteen',
          19 : 'nineteen', 20 : 'twenty',
          30 : 'thirty', 40 : 'forty', 50 : 'fifty', 60 : 'sixty',
          70 : 'seventy', 80 : 'eighty', 90 : 'ninety' }
    k = 1000
    m = k * 1000
    b = m * 1000
    t = b * 1000

    assert(0 <= num)

    if (num < 20):
        return d[num]

    if (num < 100):
        if num % 10 == 0: return d[num]
        else: return d[num // 10 * 10] + '-' + d[num % 10]

    if (num < k):
        if num % 100 == 0: return d[num // 100] + ' hundred'
        else: return d[num // 100] + ' hundred and ' + int_to_en(num % 100)

    if (num < m):
        if num % k == 0: return int_to_en(num // k) + ' thousand'
        else: return int_to_en(num // k) + ' thousand, ' + int_to_en(num % k)

    if (num < b):
        if (num % m) == 0: return int_to_en(num // m) + ' million'
        else: return int_to_en(num // m) + ' million, ' + int_to_en(num % m)

    if (num < t):
        if (num % b) == 0: return int_to_en(num // b) + ' billion'
        else: return int_to_en(num // b) + ' billion, ' + int_to_en(num % b)

    if (num % t == 0): return int_to_en(num // t) + ' trillion'
    else: return int_to_en(num // t) + ' trillion, ' + int_to_en(num % t)

    raise AssertionError('num is too large: %s' % str(num))

def main():
    num = int(input("Enter a number: "))
    if num<0:
        print("minus "+int_to_en(abs(num)))
    else:
        print(int_to_en(num))

if __name__ == "__main__":
    main()

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